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Free Quantitative Aptitude questions with answers for MBA CET

Arithmetic, algebra, geometry, number systems, permutation and combination, probability and data interpretation - the quant questions that decide your MBA CET percentile. These 117 questions are also useful for CAT, MAT and ATMA. Tap “Show answer” under any question for the correct option and the explanation.

  1. Question 41

    If A:B = 2:3 and B:C = 4:5, then what is A:C?
    • (A)8:15
    • (B)3:5
    • (C)4:5
    • (D)2:5
    Show answer and explanation

    Correct answer: (A) 8:15

    Make B the same: A:B = 8:12, B:C = 12:15 → A:C = 8:15.

  2. Question 42

    If the simple interest on ₹5000 in 3 years is ₹600, what is the rate of interest per annum?
    • (A)3%
    • (B)4%
    • (C)5%
    • (D)6%
    Show answer and explanation

    Correct answer: (B) 4%

    SI = (P×R×T)/100 → 600 = (5000×R×3)/100 → 600 = 150R → R = 4%.

  3. Question 43

    A train 150 m long is running at 54 km/h. How much time will it take to cross a pole?
    • (A)8 sec
    • (B)10 sec
    • (C)5 sec
    • (D)12 sec
    Show answer and explanation

    Correct answer: (B) 10 sec

    54 km/h = 54 × 5/18 = 15 m/s. Time = 150 ÷ 15 = 10 sec.

  4. Question 44

    If A can do a job in 10 days and B can do it in 15 days, how long will they take working alternately, starting with A?
    • (A)11 days
    • (B)10 days
    • (C)9 days
    • (D)12 days
    Show answer and explanation

    Correct answer: (D) 12 days

    A's 1-day work = 1/10, B's = 1/15. In 2 days they finish 1/10+1/15 = 1/6. In 10 days (5 cycles) they complete 5/6. Remaining 1/6: Day 11 (A) does 1/10, leaving 1/15; Day 12 (B) does 1/15 - work completed on day 12.

  5. Question 45

    The table below shows a company's sales for five years. Year 2019 2020 2021 2022 2023 Sales (₹ Lakhs) 120 150 180 210 240 What is the average sales of the company over the 5 years?
    • (A)160
    • (B)170
    • (C)180
    • (D)190
    Show answer and explanation

    Correct answer: (C) 180

    Average = total sales ÷ number of years = 900/5 = 180.

  6. Question 46

    Using the same sales table as the previous question, Year 2019 2020 2021 2022 2023 Sales (₹ Lakhs) 120 150 180 210 240 in which year did sales increase by the highest amount compared to the previous year?
    • (A)2020
    • (B)2021
    • (C)2022
    • (D)All (tied)
    Show answer and explanation

    Correct answer: (D) All (tied)

    Sales rose by ₹30 Lakhs every year (120→150→180→210→240), so every year is tied for the highest increase.

  7. Question 47

    Using the same sales table, Year 2019 2020 2021 2022 2023 Sales (₹ Lakhs) 120 150 180 210 240 what is the percentage increase in sales from 2019 to 2023?
    • (A)80%
    • (B)90%
    • (C)100%
    • (D)120%
    Show answer and explanation

    Correct answer: (C) 100%

    % increase = (240 − 120)/120 × 100 = 100%.

  8. Question 48

    Using the same sales table, Year 2019 2020 2021 2022 2023 Sales (₹ Lakhs) 120 150 180 210 240 the ratio of sales in 2021 to sales in 2019 is:
    • (A)2:1
    • (B)3:2
    • (C)5:3
    • (D)4:3
    Show answer and explanation

    Correct answer: (B) 3:2

    180 : 120 = 3 : 2.

  9. Question 49

    Find the odd man out. 10, 25, 45, 54, 60, 75, 80
    • (A)10
    • (B)45
    • (C)54
    • (D)75
    Show answer and explanation

    Correct answer: (C) 54

    All numbers except 54 are multiples of 5 (10, 25, 45, 60, 75, 80). 54 is not, so it doesn't fit.

  10. Question 50

    Find the wrong number in the given sequence of numbers. 36, 54, 18, 27, 9, 18.5, 4.5
    • (A)4.5
    • (B)18.5
    • (C)54
    • (D)18
    Show answer and explanation

    Correct answer: (B) 18.5

    The pattern alternates ×1.5 and ÷3: 36→54→18→27→9→13.5 (expected) →4.5. The given 18.5 breaks that pattern, so 18.5 is the wrong number.

  11. Question 51

    Find the next number in the pattern: 8, 24, 12, 36, 18, 54, (....)
    • (A)27
    • (B)108
    • (C)68
    • (D)72
    Show answer and explanation

    Correct answer: (A) 27

    The pattern alternates ×3 and ÷2: 8→24(×3)→12(÷2)→36(×3)→18(÷2)→54(×3)→27(÷2).

  12. Question 52

    In the given question, two quantities are given, one as ‘Quantity I’ and another as ‘Quantity II’. You have to determine relationship between two quantities and choose the appropriate option: Quantity I − Train A cross a plaƞorm of length 520 meters and a man in 22.8 sec and 7.2 sec respectively.109/66 Quantity II − If train A cross train B running in same direction at 96 km/hr in 63 seconds then find the length of train B. – What is length of train C having speed of 90 km/hr and cross train A in 7.2 sec running in opposite direction.
    • (A)Quantity I > Quantity II
    • (B)Quantity I < Quantity II
    • (C)Quantity I ≥ Quantity II
    • (D)Quantity I ≤ Quantity II
    • (E)Quantity I = Quantity II or no relation
    Show answer and explanation

    Correct answer: (E) Quantity I = Quantity II or no relation

    Train A: speed = 520 / (22.8 - 7.2) = 33.33 m/s = 120 km/h, and its length = 33.33 x 7.2 = 240 m. Train B (same direction at 96 km/h): relative speed = 24 km/h = 6.67 m/s, so the distance covered in 63 s is 420 m, which is the length of A plus B. Length of B = 420 - 240 = 180 m. Train C (opposite direction at 90 km/h): relative speed = 210 km/h = 58.33 m/s, so the distance covered in 7.2 s is 420 m. Length of C = 420 - 240 = 180 m. The two lengths are equal.

  13. Question 53

    Ratio of age of Bhavya & Veer three years ago was 7 : 8 and after six year it will be 10 : 11. Ankit is two years older than Bhavya, while Ayush is four years younger than that of Veer. The time when Bhavya and Veer completed their graduation, the ratio of their respective ages at that time was 20 : 23 Quantity I − Sum of age of Ankit & Ayush at the time when Bhavya & Veer respectively completed their graduation. Quantity II − Average age of P, Q & R, two years hence will be 38 years and ratio of present age of Q & R be 16 : 9. P is 33 years old, ratio of age of R & T eight years hence will be 7 : 8. M is four years older than Q and ratio of present age of M & N is 13 :14. Find average age of N & Q.
    • (A)Quantity I > Quantity II
    • (B)Quantity I < Quantity II
    • (C)Quantity I ≥ Quantity II
    • (D)Quantity I ≤ Quantity II
    • (E)Quantity I = Quantity II or no relation
    Show answer and explanation

    Correct answer: (B) Quantity I < Quantity II

    Bhavya and Veer: 8(B - 3) = 7(V - 3) and 11(B + 6) = 10(V + 6) give V = 27 and B = 24. Ankit = 26, Ayush = 23. At graduation the ratio 20 : 23 with a difference of 3 years gives 20 and 23, so graduation was 4 years ago. Ankit then 22, Ayush then 19: Quantity I = 41. P, Q, R two years hence average 38, so the present sum is 108; P = 33 gives Q + R = 75 and with 16 : 9, Q = 48 and R = 27. M = 52, and M : N = 13 : 14 gives N = 56. Average of N and Q = 52: Quantity II = 52. Quantity I < Quantity II.

  14. Question 54

    Length of body diagonal of a cube is 60√3 cm, if cube is melted and formed some smaller cubes with side of 4 cm each or cube is melted and formed some cuboids of each having length of 8 cm, width of 5 cm & height of 2 cm. Quantity I − Find the difference between increase in total surface area of all smaller cubes with respect to original cube & increase in total surface area of all cuboids formed with respect to original cube (in m²). Quantity II − 3.16 m2
    • (A)Quantity I > Quantity II
    • (B)Quantity I < Quantity II
    • (C)Quantity I ≥ Quantity II
    • (D)Quantity I ≤ Quantity II
    • (E)Quantity I = Quantity II or no relation
    Show answer and explanation

    Correct answer: (A) Quantity I > Quantity II

    Body diagonal 60 root 3 gives a side of 60 cm, volume 216000 cm3 and surface area 21600 cm2. Small cubes of side 4: 3375 cubes with total surface area 324000 cm2, an increase of 302400 cm2. Cuboids 8 x 5 x 2 (volume 80): 2700 cuboids with surface area 132 each, 356400 cm2 in total, an increase of 334800 cm2. Difference = 334800 - 302400 = 32400 cm2 = 3.24 m2, which is more than 3.16 m2.

  15. Question 55

    A circle with center ‘o’ is circumscribed with an equilateral triangle ABC of side 24√3 cm109/66 Quantity I − Find the height of triangle (in cm). Quantity II – Find the length of rectangle (in cm) having perimeter 120 cm and breadth equal to radius of circle.
    • (A)Quantity I > Quantity II
    • (B)Quantity I < Quantity II
    • (C)Quantity I ≥ Quantity II
    • (D)Quantity I ≤ Quantity II
    • (E)Quantity I = Quantity II or no relation
    Show answer and explanation

    Correct answer: (E) Quantity I = Quantity II or no relation

    For an equilateral triangle of side 24 root 3: height = (root 3 / 2) x 24 root 3 = 36 cm, and the circumradius is 24 cm. Rectangle: perimeter 120 and breadth 24 give length = 60 - 24 = 36 cm. Both quantities are 36.

  16. Question 56

    Quantity I: A man has two solid balls. Ratio between radius of first ball and second ball is 4 : 3. If man cut the second ball from middle then difference between total surface area of first ball and total surface area of a part of second ball is 1424.5 cm². Find radius of bigger ball? Quantity II: Height of a cylindrical vessel is equal to side of a square, having area is 256 cm². If volume of cylindrical vessel is 22176 cm³ then find the radius of cylindrical vessel.
    • (A)Quantity I > Quantity II
    • (B)Quantity I < Quantity II
    • (C)Quantity I ≥ Quantity II
    • (D)Quantity I ≤ Quantity II
    • (E)Quantity I = Quantity II or no relation
    Show answer and explanation

    Correct answer: (B) Quantity I < Quantity II

    Quantity I: radii 4k and 3k. Surface area of the whole ball 4 pi (4k)^2 = 64 pi k^2; a half of the second ball has surface area 3 pi (3k)^2 = 27 pi k^2. The difference 37 pi k^2 = 1424.5 gives k^2 = 12.25, k = 3.5, so the bigger radius = 14 cm. Quantity II: the square of area 256 has side 16, so height = 16. Volume 22176 = pi r^2 x 16 gives r^2 = 441 and r = 21 cm. 14 < 21, so Quantity I < Quantity II.

  17. Question 57

    110, 55, 55, 110, ? , 3520
    • (A)425
    • (B)380
    • (C)440
    • (D)None of these
    • (E)450
    Show answer and explanation

    Correct answer: (C) 440

    Each term is the previous term multiplied by 1/2, 1, 2, 4, 8: 110 x 1/2 = 55, 55 x 1 = 55, 55 x 2 = 110, 110 x 4 = 440, 440 x 8 = 3520. So the missing term is 440.

  18. Question 58

    8, 5, 7, 18, 80, ?
    • (A)656
    • (B)None of these
    • (C)126
    • (D)642
    • (E)428
    Show answer and explanation

    Correct answer: (A) 656

    The pattern is x0.5 + 1, x1 + 2, x2 + 4, x4 + 8, x8 + 16: 8 x 0.5 + 1 = 5, 5 + 2 = 7, 7 x 2 + 4 = 18, 18 x 4 + 8 = 80, 80 x 8 + 16 = 656.

  19. Question 59

    11, 12, 17, 30, 59, ?
    • (A)None of these
    • (B)125
    • (C)120
    • (D)100
    • (E)110
    Show answer and explanation

    Correct answer: (C) 120

    The differences are 1, 5, 13, 29, and these differences themselves increase by 4, 8, 16 (doubling). The next increase is 32, so the next difference is 61 and the next term is 59 + 61 = 120.

  20. Question 60

    1680, 1168, 1119, 903, ? , 814
    • (A)None of these
    • (B)864
    • (C)814
    • (D)878
    • (E)858
    Show answer and explanation

    Correct answer: (D) 878

    The differences are 512 (8 cubed), 49 (7 squared), 216 (6 cubed), 25 (5 squared), 64 (4 cubed). So 903 - 25 = 878, and 878 - 814 = 64.

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