Free Quantitative Aptitude questions with answers for MBA CET
Arithmetic, algebra, geometry, number systems, permutation and combination, probability and data interpretation - the quant questions that decide your MBA CET percentile. These 117 questions are also useful for CAT, MAT and ATMA. Tap “Show answer” under any question for the correct option and the explanation.
Question 21
If there are 63 litres of milk in a drum with a milk-to-water ratio of 7:9, what is the quantity of water in this mixture?- (A)63 litres
- (B)79 litres
- (C)81 litres
- (D)98 litres
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Correct answer: (C) 81 litres
Milk fraction = 7/16, so total mixture = 63 ÷ (7/16) = 144 litres. Water = 144 − 63 = 81 litres.Question 22
A recipe for a smoothie calls for 1 cup of strawberries for every 2 cups of milk. If you want to make a smoothie using 4 cups of strawberries, then how many cups of milk should you use?- (A)2
- (B)4
- (C)6
- (D)8
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Correct answer: (D) 8
Ratio strawberries:milk = 1:2, so 4 cups strawberries need 4 × 2 = 8 cups milk.Question 23
A person invested ₹25,800 for 1 2/5 years at 13 4/7% rate of simple interest, then what is the total amount (in ₹) received by the person?- (A)30,722
- (B)30,720
- (C)30,072
- (D)30,702
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Correct answer: (D) 30,702
Time = 7/5 years, Rate = 95/7%. SI = (25800 × 95/7 × 7/5)/100 = (25800 × 19)/100 = ₹4,902. Amount = 25,800 + 4,902 = ₹30,702.Question 24
The ratio of the compound interest accrued for 2 years and the simple interest accrued for 1 year on the same amount at r% p.a. is 2.21. What is the value of r?- (A)21
- (B)11
- (C)20
- (D)10
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Correct answer: (A) 21
CI(2yr)/SI(1yr) = 2 + r/100. Setting 2 + r/100 = 2.21 gives r = 21.Question 25
The ratio between the speeds of two trains is 3:5. If the second train runs 300 km in 4 hours, then the speed of the first train (in km/h) is:- (A)35
- (B)45
- (C)55
- (D)65
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Correct answer: (B) 45
Speed of second train = 300/4 = 75 km/h. Speed of first train = (3/5) × 75 = 45 km/h.Question 26
4 women and 3 men can do a piece of work in 20 days while 2 women and 4 men can do the same piece of work in 30 days. How much time will be taken by 7 women and 9 men to do the same piece of work?- (A)21 days
- (B)18 days
- (C)15 days
- (D)10 days
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Correct answer: (D) 10 days
Solving 4w+3m=1/20 and 2w+4m=1/30 gives w=1/100, m=1/300 (work/day). 7w+9m = 7/100+9/300 = 1/10, so the job takes 10 days.Question 27
What is the simplified value of [{(11 5/7 − 8 3/14) × (5/8 − 19/56)} of 0.75]?- (A)0.2
- (B)0.25
- (C)0.5
- (D)0.75
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Correct answer: (D) 0.75
11 5/7 − 8 3/14 = 82/7 − 115/14 = 49/14 = 3.5. 5/8 − 19/56 = 35/56 − 19/56 = 16/56 = 2/7. 3.5 × 2/7 = 1. 1 of 0.75 = 0.75.Question 28
Which symbol among the expanded form of the acronym 'BODMAS' should replace '#' in the given expression? (26/33 − 1 19/27) {3/11 − (6 ÷ 22/7)} # 0.09 = −1- (A)OF
- (B)DIVISION
- (C)SUBTRACTION
- (D)ADDITION
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Correct answer: (D) ADDITION
Following BODMAS order, the operation that correctly completes the expression is Addition.Question 29
Below is given the frequency distribution of weights of a group of 81 students of a class in a school. Find the modal class. Weight (kg) No. of students 30–34 5 35–39 10 40–44 16 45–49 18 50–54 20 55–59 4 60–64 8- (A)35-39
- (B)40-44
- (C)45-49
- (D)50-54
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Correct answer: (D) 50-54
The modal class is the one with the highest frequency. The highest frequency (20) belongs to 50-54.Question 30
Calculate the range and its coefficient of A's monthly earnings for a year. Month 1 2 3 4 5 6 7 8 Earning (in ₹00s) 110 125 135 156 158 165 170 180- (A)7000, 0.2414
- (B)7200, 0.2413
- (C)7000, 0.2568
- (D)7200, 0.2568
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Correct answer: (A) 7000, 0.2414
Range = 18,000 − 11,000 = 7,000. Coefficient of range = 7,000 / (18,000 + 11,000) = 7,000/29,000 ≈ 0.2414.Question 31
The mean of 150 items is 45 and their standard deviation is 3.5. Find its sum and sum of squares of all observations.- (A)6250, 305567.5
- (B)6750, 304587.5
- (C)6250, 305587.5
- (D)6750, 305587.5
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Correct answer: (D) 6750, 305587.5
Sum = mean × n = 45 × 150 = 6,750. Sum of squares = n × (SD² + mean²) = 150 × (12.25 + 2025) = 305,587.5.Question 32
The table below shows the number of persons taking personal loans from five banks over four years. Which bank recorded the least number of people taking personal loans from 1991 to 1994? Year Bank A Bank B Bank C Bank D Bank E 1991 26000 30000 22500 28000 32000 1992 32000 31500 25000 25800 33000 1993 36000 28000 27000 35000 31000 1994 30000 25500 35200 25800 32200- (A)Bank B
- (B)Bank C
- (C)Bank A
- (D)Bank D
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Correct answer: (B) Bank C
Four-year totals: A=124000, B=115000, C=109700, D=114600, E=128200. The lowest total is Bank C at 109,700.Question 33
Using the same bank-loan table as the previous question, the percentage of the total number of people taking loans from Bank B compared to the total from all banks in all the above years is: (round to one decimal) Year Bank A Bank B Bank C Bank D Bank E 1991 26000 30000 22500 28000 32000 1992 32000 31500 25000 25800 33000 1993 36000 28000 27000 35000 31000 1994 30000 25500 35200 25800 32200- (A)20.8%
- (B)19.3%
- (C)18.9%
- (D)19.9%
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Correct answer: (B) 19.3%
Total across all banks = 124000+115000+109700+114600+128200 = 591,500. Bank B share = 115000/591500 × 100 ≈ 19.3%.Question 34
If 3x + 7 = 25, find the value of x.- (A)6
- (B)7
- (C)8
- (D)9
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Correct answer: (A) 6
3x + 7 = 25 → 3x = 18 → x = 6.Question 35
The average of 5 numbers is 27. If one number is 35, what is the average of the remaining four numbers?- (A)25
- (B)26
- (C)27
- (D)28
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Correct answer: (A) 25
Total of 5 numbers = 5 × 27 = 135. Remaining four = 135 − 35 = 100. Average = 100 ÷ 4 = 25.Question 36
If the speed of a car is increased by 20%, how much less time will it take to cover the same distance?- (A)16.66%
- (B)20%
- (C)25%
- (D)10%
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Correct answer: (A) 16.66%
Let speed = v, time = t. New speed = 1.2v → new time = t/1.2 ≈ 0.8333t. Reduction = 1 − 0.8333 = 16.66%.Question 37
The ratio of ages of A and B is 3:4. If A is 21 years old, find B's age.- (A)24
- (B)25
- (C)28
- (D)30
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Correct answer: (C) 28
3 parts = 21 → 1 part = 7 → B = 4 × 7 = 28.Question 38
The simple interest on Rs. 5000 at 10% per annum for 3 years is?- (A)1500
- (B)1200
- (C)1000
- (D)1600
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Correct answer: (A) 1500
SI = (P × R × T)/100 = (5000 × 10 × 3)/100 = 1500.Question 39
A number is increased by 25% and then decreased by 20%. What is the net percentage change?- (A)0%
- (B)5% increase
- (C)10% increase
- (D)10% decrease
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Correct answer: (A) 0%
Start with 100 → after +25% → 125 → after −20% → 100. No change → 0%.Question 40
A trader marks his goods 20% above cost price and allows a discount of 10%. His gain percent is:- (A)8%
- (B)10%
- (C)12%
- (D)15%
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Correct answer: (A) 8%
Cost = 100 → MP = 120 → SP = 120 × 0.9 = 108. Profit = 8, so profit% = 8%.
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